Find the Inverse y = natural log of x-5+3

Rewrite the equation as ${\displaystyle \ln (y-5)+3=x}$.

Subtract ${\displaystyle 3}$ from both sides of the equation.

To solve for ${\displaystyle y}$, rewrite the equation using properties of logarithms.

Rewrite ${\displaystyle \ln (y-5)=x-3}$ in exponential form using the definition of a logarithm. If ${\displaystyle x}$ and ${\displaystyle b}$ are positive real numbers and ${\displaystyle b\ne 1}$, then ${\displaystyle {\log }_b\left(x\right)=y}$ is equivalent to ${\displaystyle b^y=x}$.

Solve for ${\displaystyle y}$.

To verify the inverse, check if ${\displaystyle f^{-1}\left(f\left(x\right)\right)=x}$ and ${\displaystyle f\left(f^{-1}\left(x\right)\right)=x}$.

Evaluate ${\displaystyle f^{-1}\left(f\left(x\right)\right)}$.

Evaluate ${\displaystyle f\left(f^{-1}\left(x\right)\right)}$.

Since ${\displaystyle f^{-1}\left(f\left(x\right)\right)=x}$ and ${\displaystyle f\left(f^{-1}\left(x\right)\right)=x}$, then ${\displaystyle f^{-1}\left(x\right)=e^{x-3}+5}$ is the inverse of ${\displaystyle f\left(x\right)=\ln (x-5)+3}$.