Find the LCM 4x^2-7 and 6x^2-5

$4 x^{2} - 7$ and $6 x^{2} - 5$

The LCM is the smallest positive number that all of the numbers divide into evenly.

1. List the prime factors of each number.

2. Multiply each factor the greatest number of times it occurs in either number.

The number $1$ is not a prime number because it only has one positive factor, which is itself.

Not prime

The LCM of $1, 1$ is the result of multiplying all prime factors the greatest number of times they occur in either number.

$1$

The factor for $4 x^{2} - 7$ is $4 x^{2} - 7$ itself.

$(4 x^{2} - 7) = 4 x^{2} - 7$

$(4 x^{2} - 7)$ occurs $1$ time.

The factor for $6 x^{2} - 5$ is $6 x^{2} - 5$ itself.

$(6 x^{2} - 5) = 6 x^{2} - 5$

$(6 x^{2} - 5)$ occurs $1$ time.

The LCM of $4 x^{2} - 7, 6 x^{2} - 5$ is the result of multiplying all factors the greatest number of times they occur in either term.

$(4 x^{2} - 7) (6 x^{2} - 5)$