Find the Mass of 1 Mole 25(atoms)(of)W

$25 (a t o ms) (o f) W$

Step 1

To find the mass of $1$ mole of $25 (a t o ms) (o f) W$ look up the atomic mass of each element and multiply it by the number of atoms contained in each element in the molecule.

mass of $1$ mole of $25 (a t o ms) (o f) W$ $=$ $(mass of ato)$ + $(mass of U)$ + $(mass of N)$ + $(mass of I)$ + $(mass of T>ms)$ + $(mass of of)$

Step 2

Fill in the atomic masses from the periodic table.

mass of $1$ mole of $25 (a t o ms) (o f) W$ $=$ $(0)$ + $(238.02999877)$ + $(14.01000022)$ + $(126.90000152)$ + $(0)$ + $(0)$

Step 3

Simplify the result.

Remove parentheses.

mass of $1$ mole of $25 (a t o ms) (o f) W = 0 + 238.02999877 + 14.01000022 + 126.90000152 + 0 + 0 g$

Add $0$ and $238.02999877$ .

mass of $1$ mole of $25 (a t o ms) (o f) W = 238.02999877 + 14.01000022 + 126.90000152 + 0 + 0 g$

Add $238.02999877$ and $14.01000022$ .

mass of $1$ mole of $25 (a t o ms) (o f) W = 252.039999 + 126.90000152 + 0 + 0 g$

Add $252.039999$ and $126.90000152$ .

mass of $1$ mole of $25 (a t o ms) (o f) W = 378.94000053 + 0 + 0 g$

Add $378.94000053$ and $0$ .

mass of $1$ mole of $25 (a t o ms) (o f) W = 378.94000053 + 0 g$

Add $378.94000053$ and $0$ .

mass of $1$ mole of $25 (a t o ms) (o f) W = 378.94000053 g$

Find the Mass of 1 Mole 25(atoms)(of)W

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