Find the Mass of 1 Mole Al(OH)_3

$A l {(O H)}_{3}$

Step 1

To find the mass of $1$ mole of $A l {(O H)}_{3}$ look up the atomic mass of each element and multiply it by the number of atoms contained in each element in the molecule.

mass of $1$ mole of $A l {(O H)}_{3}$ $=$ $(mass of Al)$ + $3 (mass of O)$ + $3 (mass of H)$

Step 2

Fill in the atomic masses from the periodic table.

mass of $1$ mole of $A l {(O H)}_{3}$ $=$ $(26.97999954)$ + $3 (16)$ + $3 (1.00999999)$

Step 3

Simplify the result.

Simplify each term.

Multiply $3$ by $16$ .

mass of $1$ mole of $A l {(O H)}_{3} = 26.97999954 + 48 + 3 (1.00999999) g$

Multiply $3$ by $1.00999999$ .

mass of $1$ mole of $A l {(O H)}_{3} = 26.97999954 + 48 + 3.02999997 g$

Simplify by adding numbers.

Add $26.97999954$ and $48$ .

mass of $1$ mole of $A l {(O H)}_{3} = 74.97999954 + 3.02999997 g$

Add $74.97999954$ and $3.02999997$ .

mass of $1$ mole of $A l {(O H)}_{3} = 78.00999951 g$

Find the Mass of 1 Mole Al(OH)_3

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