Find the Mass of 1 Mole C_3H_6O

$C_{3} H_{6} O$

Step 1

To find the mass of $1$ mole of $C_{3} H_{6} O$ look up the atomic mass of each element and multiply it by the number of atoms contained in each element in the molecule.

mass of $1$ mole of $C_{3} H_{6} O$ $=$ $3 (mass of C)$ + $6 (mass of H)$ + $(mass of O)$

Step 2

Fill in the atomic masses from the periodic table.

mass of $1$ mole of $C_{3} H_{6} O$ $=$ $3 (12.01000022)$ + $6 (1.00999999)$ + $(16)$

Step 3

Simplify the result.

Remove parentheses.

mass of $1$ mole of $C_{3} H_{6} O = 3 (12.01000022) + 6 (1.00999999) + 16 g$

Simplify each term.

Multiply $3$ by $12.01000022$ .

mass of $1$ mole of $C_{3} H_{6} O = 36.03000068 + 6 (1.00999999) + 16 g$

Multiply $6$ by $1.00999999$ .

mass of $1$ mole of $C_{3} H_{6} O = 36.03000068 + 6.05999994 + 16 g$

Simplify by adding numbers.

Add $36.03000068$ and $6.05999994$ .

mass of $1$ mole of $C_{3} H_{6} O = 42.09000062 + 16 g$

Add $42.09000062$ and $16$ .

mass of $1$ mole of $C_{3} H_{6} O = 58.09000062 g$

Find the Mass of 1 Mole C_3H_6O

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