Find the Mass of 1 Mole Co(NO_3)(2(aq))

$C o (N O_{3}) (2 (a q))$

Step 1

To find the mass of $1$ mole of $C o (N O_{3}) (2 (a q))$ look up the atomic mass of each element and multiply it by the number of atoms contained in each element in the molecule.

mass of $1$ mole of $C o (N O_{3}) (2 (a q))$ $=$ $(mass of Co)$ + $(mass of N)$ + $3 (mass of O)$ + $(mass of aq)$

Step 2

Fill in the atomic masses from the periodic table.

mass of $1$ mole of $C o (N O_{3}) (2 (a q))$ $=$ $(58.9300003)$ + $(14.01000022)$ + $3 (16)$ + $(0)$

Step 3

Simplify the result.

Remove parentheses.

mass of $1$ mole of $C o (N O_{3}) (2 (a q)) = 58.9300003 + 14.01000022 + 3 (16) + 0 g$

Multiply $3$ by $16$ .

mass of $1$ mole of $C o (N O_{3}) (2 (a q)) = 58.9300003 + 14.01000022 + 48 + 0 g$

Add $58.9300003$ and $14.01000022$ .

mass of $1$ mole of $C o (N O_{3}) (2 (a q)) = 72.94000053 + 48 + 0 g$

Add $72.94000053$ and $48$ .

mass of $1$ mole of $C o (N O_{3}) (2 (a q)) = 120.94000053 + 0 g$

Add $120.94000053$ and $0$ .

mass of $1$ mole of $C o (N O_{3}) (2 (a q)) = 120.94000053 g$

Find the Mass of 1 Mole Co(NO_3)(2(aq))

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