Find the Mass of 1 Mole Fe_2(SO_4)_3

$F e_{2} {(S O_{4})}_{3}$

Step 1

To find the mass of $1$ mole of $F e_{2} {(S O_{4})}_{3}$ look up the atomic mass of each element and multiply it by the number of atoms contained in each element in the molecule.

Step 2

Fill in the atomic masses from the periodic table.

Step 3

Simplify the result.

Simplify each term.

Multiply $2$ by $55.84999847$ .

mass of $1$ mole of $F e_{2} {(S O_{4})}_{3} = 111.69999694 + 3 (32.06999969) + 12 (16) g$

Multiply $3$ by $32.06999969$ .

mass of $1$ mole of $F e_{2} {(S O_{4})}_{3} = 111.69999694 + 96.20999908 + 12 (16) g$

Multiply $12$ by $16$ .

mass of $1$ mole of $F e_{2} {(S O_{4})}_{3} = 111.69999694 + 96.20999908 + 192 g$

Simplify by adding numbers.

Add $111.69999694$ and $96.20999908$ .

mass of $1$ mole of $F e_{2} {(S O_{4})}_{3} = 207.90999603 + 192 g$

Add $207.90999603$ and $192$ .

mass of $1$ mole of $F e_{2} {(S O_{4})}_{3} = 399.90999603 g$

Find the Mass of 1 Mole Fe_2(SO_4)_3

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