Find the Mass of 1 Mole H_3PO_4

$H_{3} P O_{4}$

Step 1

To find the mass of $1$ mole of $H_{3} P O_{4}$ look up the atomic mass of each element and multiply it by the number of atoms contained in each element in the molecule.

mass of $1$ mole of $H_{3} P O_{4}$ $=$ $3 (mass of H)$ + $(mass of P)$ + $4 (mass of O)$

Step 2

Fill in the atomic masses from the periodic table.

mass of $1$ mole of $H_{3} P O_{4}$ $=$ $3 (1.00999999)$ + $(30.96999931)$ + $4 (16)$

Step 3

Simplify the result.

Remove parentheses.

mass of $1$ mole of $H_{3} P O_{4} = 3 (1.00999999) + 30.96999931 + 4 (16) g$

Simplify each term.

Multiply $3$ by $1.00999999$ .

mass of $1$ mole of $H_{3} P O_{4} = 3.02999997 + 30.96999931 + 4 (16) g$

Multiply $4$ by $16$ .

mass of $1$ mole of $H_{3} P O_{4} = 3.02999997 + 30.96999931 + 64 g$

Simplify by adding numbers.

Add $3.02999997$ and $30.96999931$ .

mass of $1$ mole of $H_{3} P O_{4} = 33.99999928 + 64 g$

Add $33.99999928$ and $64$ .

mass of $1$ mole of $H_{3} P O_{4} = 97.99999928 g$

Find the Mass of 1 Mole H_3PO_4

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