Find the Mass of 1 Mole Na_2CO_3

$N a_{2} C O_{3}$

Step 1

To find the mass of $1$ mole of $N a_{2} C O_{3}$ look up the atomic mass of each element and multiply it by the number of atoms contained in each element in the molecule.

mass of $1$ mole of $N a_{2} C O_{3}$ $=$ $2 (mass of Na)$ + $(mass of C)$ + $3 (mass of O)$

Step 2

Fill in the atomic masses from the periodic table.

mass of $1$ mole of $N a_{2} C O_{3}$ $=$ $2 (22.98999977)$ + $(12.01000022)$ + $3 (16)$

Step 3

Simplify the result.

Remove parentheses.

mass of $1$ mole of $N a_{2} C O_{3} = 2 (22.98999977) + 12.01000022 + 3 (16) g$

Simplify each term.

Multiply $2$ by $22.98999977$ .

mass of $1$ mole of $N a_{2} C O_{3} = 45.97999954 + 12.01000022 + 3 (16) g$

Multiply $3$ by $16$ .

mass of $1$ mole of $N a_{2} C O_{3} = 45.97999954 + 12.01000022 + 48 g$

Simplify by adding numbers.

Add $45.97999954$ and $12.01000022$ .

mass of $1$ mole of $N a_{2} C O_{3} = 57.98999977 + 48 g$

Add $57.98999977$ and $48$ .

mass of $1$ mole of $N a_{2} C O_{3} = 105.98999977 g$

Find the Mass of 1 Mole Na_2CO_3

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