Find the Mass of 1 Mole NaBrO

$N a B r O$

Step 1

To find the mass of $1$ mole of $N a B r O$ look up the atomic mass of each element and multiply it by the number of atoms contained in each element in the molecule.

mass of $1$ mole of $N a B r O$ $=$ $(mass of Na)$ + $(mass of Br)$ + $(mass of O)$

Step 2

Fill in the atomic masses from the periodic table.

mass of $1$ mole of $N a B r O$ $=$ $(22.98999977)$ + $(79.90000152)$ + $(16)$

Step 3

Simplify the result.

Remove parentheses.

mass of $1$ mole of $N a B r O = 22.98999977 + 79.90000152 + 16 g$

Add $22.98999977$ and $79.90000152$ .

mass of $1$ mole of $N a B r O = 102.89000129 + 16 g$

Add $102.89000129$ and $16$ .

mass of $1$ mole of $N a B r O = 118.89000129 g$

Find the Mass of 1 Mole NaBrO

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