Find the Mass Percentages B_2H_6

$B_{2} H_{6}$

Step 1

To find the mass of $1$ mole of $B_{2} H_{6}$ look up the atomic mass of each element and multiply it by the number of atoms contained in each element in the molecule.

mass of $1$ mole of $B_{2} H_{6}$ $=$ $2 (mass of B)$ + $6 (mass of H)$

Step 2

Fill in the atomic masses from the periodic table.

mass of $1$ mole of $B_{2} H_{6}$ $=$ $2 (10.81000041)$ + $6 (1.00999999)$

Step 3

Simplify the result.

Simplify each term.

Multiply $2$ by $10.81000041$ .

mass of $1$ mole of $B_{2} H_{6} = 21.62000083 + 6 (1.00999999) g$

Multiply $6$ by $1.00999999$ .

mass of $1$ mole of $B_{2} H_{6} = 21.62000083 + 6.05999994 g$

Add $21.62000083$ and $6.05999994$ .

mass of $1$ mole of $B_{2} H_{6} = 27.68000078 g$

Step 4

Find the mass percentage of $B$ .

The mass composition percentage is the mass of $B$ divided by the mass of the entire molecule converted to a percentage.

Mass percentage of $B = \frac{21.62}{27.68000078} \cdot 100$

Divide $21.62$ by $27.68000078$ .

$0.78106934 \cdot 100$

Multiply $0.78106934$ by $100$ .

$78.1069342$

Set the number as a percent.

Mass percentage of $B = 78.1069342 %$

Step 5

Find the mass percentage of $H$ .

The mass composition percentage is the mass of $H$ divided by the mass of the entire molecule converted to a percentage.

Mass percentage of $H = \frac{6.06}{27.68000078} \cdot 100$

Divide $6.06$ by $27.68000078$ .

$0.21893062 \cdot 100$

Multiply $0.21893062$ by $100$ .

$21.89306296$

Set the number as a percent.

Mass percentage of $H = 21.89306296 %$

Step 6

Find the mass percentage of each element in the molecule.

Mass percentage of $B = 78.1069342 %$

Mass percentage of $H = 21.89306296 %$

Find the Mass Percentages B_2H_6

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