Find the Mass Percentages C_14H_14N_3O_3SNa

$C_{14} H_{14} N_{3} O_{3} S N a$

Step 1

To find the mass of $1$ mole of $C_{14} H_{14} N_{3} O_{3} S N a$ look up the atomic mass of each element and multiply it by the number of atoms contained in each element in the molecule.

mass of $1$ mole of $C_{14} H_{14} N_{3} O_{3} S N a$ $=$ $14 (mass of C)$ + $14 (mass of H)$ + $3 (mass of N)$ + $3 (mass of O)$ + $(mass of S)$ + $(mass of Na)$

Step 2

Fill in the atomic masses from the periodic table.

mass of $1$ mole of $C_{14} H_{14} N_{3} O_{3} S N a$ $=$ $14 (12.01000022)$ + $14 (1.00999999)$ + $3 (14.01000022)$ + $3 (16)$ + $(32.06999969)$ + $(22.98999977)$

Step 3

Simplify the result.

Remove parentheses.

mass of $1$ mole of $C_{14} H_{14} N_{3} O_{3} S N a = 14 (12.01000022) + 14 (1.00999999) + 3 (14.01000022) + 3 (16) + 32.06999969 + 22.98999977 g$

Simplify each term.

Multiply $14$ by $12.01000022$ .

mass of $1$ mole of $C_{14} H_{14} N_{3} O_{3} S N a = 168.1400032 + 14 (1.00999999) + 3 (14.01000022) + 3 (16) + 32.06999969 + 22.98999977 g$

Multiply $14$ by $1.00999999$ .

mass of $1$ mole of $C_{14} H_{14} N_{3} O_{3} S N a = 168.1400032 + 14.13999986 + 3 (14.01000022) + 3 (16) + 32.06999969 + 22.98999977 g$

Multiply $3$ by $14.01000022$ .

mass of $1$ mole of $C_{14} H_{14} N_{3} O_{3} S N a = 168.1400032 + 14.13999986 + 42.03000068 + 3 (16) + 32.06999969 + 22.98999977 g$

Multiply $3$ by $16$ .

mass of $1$ mole of $C_{14} H_{14} N_{3} O_{3} S N a = 168.1400032 + 14.13999986 + 42.03000068 + 48 + 32.06999969 + 22.98999977 g$

Simplify by adding numbers.

Add $168.1400032$ and $14.13999986$ .

mass of $1$ mole of $C_{14} H_{14} N_{3} O_{3} S N a = 182.28000307 + 42.03000068 + 48 + 32.06999969 + 22.98999977 g$

Add $182.28000307$ and $42.03000068$ .

mass of $1$ mole of $C_{14} H_{14} N_{3} O_{3} S N a = 224.31000375 + 48 + 32.06999969 + 22.98999977 g$

Add $224.31000375$ and $48$ .

mass of $1$ mole of $C_{14} H_{14} N_{3} O_{3} S N a = 272.31000375 + 32.06999969 + 22.98999977 g$

Add $272.31000375$ and $32.06999969$ .

mass of $1$ mole of $C_{14} H_{14} N_{3} O_{3} S N a = 304.38000345 + 22.98999977 g$

Add $304.38000345$ and $22.98999977$ .

mass of $1$ mole of $C_{14} H_{14} N_{3} O_{3} S N a = 327.37000322 g$

Step 4

Find the mass percentage of $C$ .

The mass composition percentage is the mass of $C$ divided by the mass of the entire molecule converted to a percentage.

Mass percentage of $C = \frac{168.14}{327.37000322} \cdot 100$

Divide $168.14$ by $327.37000322$ .

$0.51360845 \cdot 100$

Multiply $0.51360845$ by $100$ .

$51.36084502$

Set the number as a percent.

Mass percentage of $C = 51.36084502 %$

Step 5

Find the mass percentage of $H$ .

The mass composition percentage is the mass of $H$ divided by the mass of the entire molecule converted to a percentage.

Mass percentage of $H = \frac{14.14}{327.37000322} \cdot 100$

Divide $14.14$ by $327.37000322$ .

$0.04319271 \cdot 100$

Multiply $0.04319271$ by $100$ .

$4.31927172$

Set the number as a percent.

Mass percentage of $H = 4.31927172 %$

Step 6

Find the mass percentage of $N$ .

The mass composition percentage is the mass of $N$ divided by the mass of the entire molecule converted to a percentage.

Mass percentage of $N = \frac{42.03}{327.37000322} \cdot 100$

Divide $42.03$ by $327.37000322$ .

$0.12838683 \cdot 100$

Multiply $0.12838683$ by $100$ .

$12.83868393$

Set the number as a percent.

Mass percentage of $N = 12.83868393 %$

Step 7

Find the mass percentage of $O$ .

The mass composition percentage is the mass of $O$ divided by the mass of the entire molecule converted to a percentage.

Mass percentage of $O = \frac{48}{327.37000322} \cdot 100$

Divide $48$ by $327.37000322$ .

$0.14662308 \cdot 100$

Multiply $0.14662308$ by $100$ .

$14.66230855$

Set the number as a percent.

Mass percentage of $O = 14.66230855 %$

Step 8

Find the mass percentage of $S$ .

The mass composition percentage is the mass of $S$ divided by the mass of the entire molecule converted to a percentage.

Mass percentage of $S = \frac{32.07}{327.37000322} \cdot 100$

Divide $32.07$ by $327.37000322$ .

$0.09796254 \cdot 100$

Multiply $0.09796254$ by $100$ .

$9.7962549$

Set the number as a percent.

Mass percentage of $S = 9.7962549 %$

Step 9

Find the mass percentage of $N a$ .

The mass composition percentage is the mass of $N a$ divided by the mass of the entire molecule converted to a percentage.

Mass percentage of $N a = \frac{22.99}{327.37000322} \cdot 100$

Divide $22.99$ by $327.37000322$ .

$0.07022634 \cdot 100$

Multiply $0.07022634$ by $100$ .

$7.02263486$

Set the number as a percent.

Mass percentage of $N a = 7.02263486 %$

Step 10

Find the mass percentage of each element in the molecule.

Mass percentage of $C = 51.36084502 %$

Mass percentage of $H = 4.31927172 %$

Mass percentage of $N = 12.83868393 %$

Mass percentage of $O = 14.66230855 %$

Mass percentage of $S = 9.7962549 %$

Mass percentage of $N a = 7.02263486 %$

Find the Mass Percentages C_14H_14N_3O_3SNa

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