Find the Mass Percentages C_2H_2Br_3

$C_{2} H_{2} B r_{3}$

Step 1

To find the mass of $1$ mole of $C_{2} H_{2} B r_{3}$ look up the atomic mass of each element and multiply it by the number of atoms contained in each element in the molecule.

mass of $1$ mole of $C_{2} H_{2} B r_{3}$ $=$ $2 (mass of C)$ + $2 (mass of H)$ + $3 (mass of Br)$

Step 2

Fill in the atomic masses from the periodic table.

mass of $1$ mole of $C_{2} H_{2} B r_{3}$ $=$ $2 (12.01000022)$ + $2 (1.00999999)$ + $3 (79.90000152)$

Step 3

Simplify the result.

Simplify each term.

Multiply $2$ by $12.01000022$ .

mass of $1$ mole of $C_{2} H_{2} B r_{3} = 24.02000045 + 2 (1.00999999) + 3 (79.90000152) g$

Multiply $2$ by $1.00999999$ .

mass of $1$ mole of $C_{2} H_{2} B r_{3} = 24.02000045 + 2.01999998 + 3 (79.90000152) g$

Multiply $3$ by $79.90000152$ .

mass of $1$ mole of $C_{2} H_{2} B r_{3} = 24.02000045 + 2.01999998 + 239.70000457 g$

Simplify by adding numbers.

Add $24.02000045$ and $2.01999998$ .

mass of $1$ mole of $C_{2} H_{2} B r_{3} = 26.04000043 + 239.70000457 g$

Add $26.04000043$ and $239.70000457$ .

mass of $1$ mole of $C_{2} H_{2} B r_{3} = 265.74000501 g$

Step 4

Find the mass percentage of $C$ .

The mass composition percentage is the mass of $C$ divided by the mass of the entire molecule converted to a percentage.

Mass percentage of $C = \frac{24.02}{265.74000501} \cdot 100$

Divide $24.02$ by $265.74000501$ .

$0.0903891 \cdot 100$

Multiply $0.0903891$ by $100$ .

$9.03891004$

Set the number as a percent.

Mass percentage of $C = 9.03891004 %$

Step 5

Find the mass percentage of $H$ .

The mass composition percentage is the mass of $H$ divided by the mass of the entire molecule converted to a percentage.

Mass percentage of $H = \frac{2.02}{265.74000501} \cdot 100$

Divide $2.02$ by $265.74000501$ .

$0.00760141 \cdot 100$

Multiply $0.00760141$ by $100$ .

$0.76014147$

Set the number as a percent.

Mass percentage of $H = 0.76014147 %$

Step 6

Find the mass percentage of $B r$ .

The mass composition percentage is the mass of $B r$ divided by the mass of the entire molecule converted to a percentage.

Mass percentage of $B r = \frac{239.7}{265.74000501} \cdot 100$

Divide $239.7$ by $265.74000501$ .

$0.90200946 \cdot 100$

Multiply $0.90200946$ by $100$ .

$90.20094659$

Set the number as a percent.

Mass percentage of $B r = 90.20094659 %$

Step 7

Find the mass percentage of each element in the molecule.

Mass percentage of $C = 9.03891004 %$

Mass percentage of $H = 0.76014147 %$

Mass percentage of $B r = 90.20094659 %$

Find the Mass Percentages C_2H_2Br_3

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