Find the Mass Percentages C_6H_12O_6

$C_{6} H_{12} O_{6}$

Step 1

To find the mass of $1$ mole of $C_{6} H_{12} O_{6}$ look up the atomic mass of each element and multiply it by the number of atoms contained in each element in the molecule.

mass of $1$ mole of $C_{6} H_{12} O_{6}$ $=$ $6 (mass of C)$ + $12 (mass of H)$ + $6 (mass of O)$

Step 2

Fill in the atomic masses from the periodic table.

mass of $1$ mole of $C_{6} H_{12} O_{6}$ $=$ $6 (12.01000022)$ + $12 (1.00999999)$ + $6 (16)$

Step 3

Simplify the result.

Simplify each term.

Multiply $6$ by $12.01000022$ .

mass of $1$ mole of $C_{6} H_{12} O_{6} = 72.06000137 + 12 (1.00999999) + 6 (16) g$

Multiply $12$ by $1.00999999$ .

mass of $1$ mole of $C_{6} H_{12} O_{6} = 72.06000137 + 12.11999988 + 6 (16) g$

Multiply $6$ by $16$ .

mass of $1$ mole of $C_{6} H_{12} O_{6} = 72.06000137 + 12.11999988 + 96 g$

Simplify by adding numbers.

Add $72.06000137$ and $12.11999988$ .

mass of $1$ mole of $C_{6} H_{12} O_{6} = 84.18000125 + 96 g$

Add $84.18000125$ and $96$ .

mass of $1$ mole of $C_{6} H_{12} O_{6} = 180.18000125 g$

Step 4

Find the mass percentage of $C$ .

The mass composition percentage is the mass of $C$ divided by the mass of the entire molecule converted to a percentage.

Mass percentage of $C = \frac{72.06}{180.18000125} \cdot 100$

Divide $72.06$ by $180.18000125$ .

$0.39993339 \cdot 100$

Multiply $0.39993339$ by $100$ .

$39.99333971$

Set the number as a percent.

Mass percentage of $C = 39.99333971 %$

Step 5

Find the mass percentage of $H$ .

The mass composition percentage is the mass of $H$ divided by the mass of the entire molecule converted to a percentage.

Mass percentage of $H = \frac{12.12}{180.18000125} \cdot 100$

Divide $12.12$ by $180.18000125$ .

$0.06726606 \cdot 100$

Multiply $0.06726606$ by $100$ .

$6.72660667$

Set the number as a percent.

Mass percentage of $H = 6.72660667 %$

Step 6

Find the mass percentage of $O$ .

The mass composition percentage is the mass of $O$ divided by the mass of the entire molecule converted to a percentage.

Mass percentage of $O = \frac{96}{180.18000125} \cdot 100$

Divide $96$ by $180.18000125$ .

$0.53280052 \cdot 100$

Multiply $0.53280052$ by $100$ .

$53.2800529$

Set the number as a percent.

Mass percentage of $O = 53.2800529 %$

Step 7

Find the mass percentage of each element in the molecule.

Mass percentage of $C = 39.99333971 %$

Mass percentage of $H = 6.72660667 %$

Mass percentage of $O = 53.2800529 %$

Find the Mass Percentages C_6H_12O_6

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