Find the Mass Percentages C_6H_6

$C_{6} H_{6}$

Step 1

To find the mass of $1$ mole of $C_{6} H_{6}$ look up the atomic mass of each element and multiply it by the number of atoms contained in each element in the molecule.

mass of $1$ mole of $C_{6} H_{6}$ $=$ $6 (mass of C)$ + $6 (mass of H)$

Step 2

Fill in the atomic masses from the periodic table.

mass of $1$ mole of $C_{6} H_{6}$ $=$ $6 (12.01000022)$ + $6 (1.00999999)$

Step 3

Simplify the result.

Simplify each term.

Multiply $6$ by $12.01000022$ .

mass of $1$ mole of $C_{6} H_{6} = 72.06000137 + 6 (1.00999999) g$

Multiply $6$ by $1.00999999$ .

mass of $1$ mole of $C_{6} H_{6} = 72.06000137 + 6.05999994 g$

Add $72.06000137$ and $6.05999994$ .

mass of $1$ mole of $C_{6} H_{6} = 78.12000131 g$

Step 4

Find the mass percentage of $C$ .

The mass composition percentage is the mass of $C$ divided by the mass of the entire molecule converted to a percentage.

Mass percentage of $C = \frac{72.06}{78.12000131} \cdot 100$

Divide $72.06$ by $78.12000131$ .

$0.92242701 \cdot 100$

Multiply $0.92242701$ by $100$ .

$92.24270197$

Set the number as a percent.

Mass percentage of $C = 92.24270197 %$

Step 5

Find the mass percentage of $H$ .

The mass composition percentage is the mass of $H$ divided by the mass of the entire molecule converted to a percentage.

Mass percentage of $H = \frac{6.06}{78.12000131} \cdot 100$

Divide $6.06$ by $78.12000131$ .

$0.07757296 \cdot 100$

Multiply $0.07757296$ by $100$ .

$7.75729633$

Set the number as a percent.

Mass percentage of $H = 7.75729633 %$

Step 6

Find the mass percentage of each element in the molecule.

Mass percentage of $C = 92.24270197 %$

Mass percentage of $H = 7.75729633 %$

Find the Mass Percentages C_6H_6

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