Find the Mass Percentages FeSO_4*7H_2O

$F e S O_{4} \cdot 7 H_{2} O$

Step 1

To find the mass of $1$ mole of $F e S O_{4} \cdot (7 H_{2} O)$ look up the atomic mass of each element and multiply it by the number of atoms contained in each element in the molecule.

mass of $1$ mole of $F e S O_{4} \cdot (7 H_{2} O)$ $=$ $(mass of Fe)$ + $(mass of S)$ + $47 (mass of O)$ + $2 (mass of H)$ + $(mass of O)$

Step 2

Fill in the atomic masses from the periodic table.

mass of $1$ mole of $F e S O_{4} \cdot (7 H_{2} O)$ $=$ $(55.84999847)$ + $(32.06999969)$ + $47 (16)$ + $2 (1.00999999)$ + $(16)$

Step 3

Simplify the result.

Remove parentheses.

mass of $1$ mole of $F e S O_{4} \cdot (7 H_{2} O) = 55.84999847 + 32.06999969 + 47 (16) + 2 (1.00999999) + 16 g$

Simplify each term.

Multiply $47$ by $16$ .

mass of $1$ mole of $F e S O_{4} \cdot (7 H_{2} O) = 55.84999847 + 32.06999969 + 752 + 2 (1.00999999) + 16 g$

Multiply $2$ by $1.00999999$ .

mass of $1$ mole of $F e S O_{4} \cdot (7 H_{2} O) = 55.84999847 + 32.06999969 + 752 + 2.01999998 + 16 g$

Simplify by adding numbers.

Add $55.84999847$ and $32.06999969$ .

mass of $1$ mole of $F e S O_{4} \cdot (7 H_{2} O) = 87.91999816 + 752 + 2.01999998 + 16 g$

Add $87.91999816$ and $752$ .

mass of $1$ mole of $F e S O_{4} \cdot (7 H_{2} O) = 839.91999816 + 2.01999998 + 16 g$

Add $839.91999816$ and $2.01999998$ .

mass of $1$ mole of $F e S O_{4} \cdot (7 H_{2} O) = 841.93999814 + 16 g$

Add $841.93999814$ and $16$ .

mass of $1$ mole of $F e S O_{4} \cdot (7 H_{2} O) = 857.93999814 g$

Step 4

Find the mass percentage of $F e$ .

The mass composition percentage is the mass of $F e$ divided by the mass of the entire molecule converted to a percentage.

Mass percentage of $F e = \frac{55.85}{857.93999814} \cdot 100$

Divide $55.85$ by $857.93999814$ .

$0.06509779 \cdot 100$

Multiply $0.06509779$ by $100$ .

$6.50977925$

Set the number as a percent.

Mass percentage of $F e = 6.50977925 %$

Step 5

Find the mass percentage of $S$ .

The mass composition percentage is the mass of $S$ divided by the mass of the entire molecule converted to a percentage.

Mass percentage of $S = \frac{32.07}{857.93999814} \cdot 100$

Divide $32.07$ by $857.93999814$ .

$0.03738023 \cdot 100$

Multiply $0.03738023$ by $100$ .

$3.73802364$

Set the number as a percent.

Mass percentage of $S = 3.73802364 %$

Step 6

Find the mass percentage of $O$ .

The mass composition percentage is the mass of $O$ divided by the mass of the entire molecule converted to a percentage.

Mass percentage of $O = \frac{768}{857.93999814} \cdot 100$

Divide $768$ by $857.93999814$ .

$0.89516749 \cdot 100$

Multiply $0.89516749$ by $100$ .

$89.51674961$

Set the number as a percent.

Mass percentage of $O = 89.51674961 %$

Step 7

Find the mass percentage of $H$ .

The mass composition percentage is the mass of $H$ divided by the mass of the entire molecule converted to a percentage.

Mass percentage of $H = \frac{2.02}{857.93999814} \cdot 100$

Divide $2.02$ by $857.93999814$ .

$0.00235447 \cdot 100$

Multiply $0.00235447$ by $100$ .

$0.2354477$

Set the number as a percent.

Mass percentage of $H = 0.2354477 %$

Step 8

Find the mass percentage of each element in the molecule.

Mass percentage of $F e = 6.50977925 %$

Mass percentage of $S = 3.73802364 %$

Mass percentage of $O = 89.51674961 %$

Mass percentage of $H = 0.2354477 %$

Find the Mass Percentages FeSO_4*7H_2O

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