Find the Mass Percentages Na_2B_4O_7

$N a_{2} B_{4} O_{7}$

Step 1

To find the mass of $1$ mole of $N a_{2} B_{4} O_{7}$ look up the atomic mass of each element and multiply it by the number of atoms contained in each element in the molecule.

mass of $1$ mole of $N a_{2} B_{4} O_{7}$ $=$ $2 (mass of Na)$ + $4 (mass of B)$ + $7 (mass of O)$

Step 2

Fill in the atomic masses from the periodic table.

mass of $1$ mole of $N a_{2} B_{4} O_{7}$ $=$ $2 (22.98999977)$ + $4 (10.81000041)$ + $7 (16)$

Step 3

Simplify the result.

Simplify each term.

Multiply $2$ by $22.98999977$ .

mass of $1$ mole of $N a_{2} B_{4} O_{7} = 45.97999954 + 4 (10.81000041) + 7 (16) g$

Multiply $4$ by $10.81000041$ .

mass of $1$ mole of $N a_{2} B_{4} O_{7} = 45.97999954 + 43.24000167 + 7 (16) g$

Multiply $7$ by $16$ .

mass of $1$ mole of $N a_{2} B_{4} O_{7} = 45.97999954 + 43.24000167 + 112 g$

Simplify by adding numbers.

Add $45.97999954$ and $43.24000167$ .

mass of $1$ mole of $N a_{2} B_{4} O_{7} = 89.22000122 + 112 g$

Add $89.22000122$ and $112$ .

mass of $1$ mole of $N a_{2} B_{4} O_{7} = 201.22000122 g$

Step 4

Find the mass percentage of $N a$ .

The mass composition percentage is the mass of $N a$ divided by the mass of the entire molecule converted to a percentage.

Mass percentage of $N a = \frac{45.98}{201.22000122} \cdot 100$

Divide $45.98$ by $201.22000122$ .

$0.22850611 \cdot 100$

Multiply $0.22850611$ by $100$ .

$22.85061113$

Set the number as a percent.

Mass percentage of $N a = 22.85061113 %$

Step 5

Find the mass percentage of $B$ .

The mass composition percentage is the mass of $B$ divided by the mass of the entire molecule converted to a percentage.

Mass percentage of $B = \frac{43.24}{201.22000122} \cdot 100$

Divide $43.24$ by $201.22000122$ .

$0.21488917 \cdot 100$

Multiply $0.21488917$ by $100$ .

$21.48891747$

Set the number as a percent.

Mass percentage of $B = 21.48891747 %$

Step 6

Find the mass percentage of $O$ .

The mass composition percentage is the mass of $O$ divided by the mass of the entire molecule converted to a percentage.

Mass percentage of $O = \frac{112}{201.22000122} \cdot 100$

Divide $112$ by $201.22000122$ .

$0.5566047 \cdot 100$

Multiply $0.5566047$ by $100$ .

$55.66047078$

Set the number as a percent.

Mass percentage of $O = 55.66047078 %$

Step 7

Find the mass percentage of each element in the molecule.

Mass percentage of $N a = 22.85061113 %$

Mass percentage of $B = 21.48891747 %$

Mass percentage of $O = 55.66047078 %$

Find the Mass Percentages Na_2B_4O_7

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