Find the Maximum/Minimum Value 3x^2+24x-6

$3 x^{2} + 24 x - 6$

Step 1

The minimum of a quadratic function occurs at $x = - \frac{b}{2 a}$ . If $a$ is positive, the minimum value of the function is $f (- \frac{b}{2 a})$ .

$f_{min}$ $x = a x^{2} + b x + c$ occurs at $x = - \frac{b}{2 a}$

Step 2

Find the value of $x = - \frac{b}{2 a}$ .

Substitute in the values of $a$ and $b$ .

$x = - \frac{24}{2 (3)}$

Remove parentheses.

$x = - \frac{24}{2 (3)}$

Simplify $- \frac{24}{2 (3)}$ .

Cancel the common factor of $24$ and $2$ .

Factor $2$ out of $24$ .

$x = - \frac{2 \cdot 12}{2 \cdot 3}$

Cancel the common factors.

Factor $2$ out of $2 \cdot 3$ .

$x = - \frac{2 \cdot 12}{2 (3)}$

Cancel the common factor.

$x = - \frac{2 \cdot 12}{2 \cdot 3}$

Rewrite the expression.

$x = - \frac{12}{3}$

Cancel the common factor of $12$ and $3$ .

Factor $3$ out of $12$ .

$x = - \frac{3 \cdot 4}{3}$

Cancel the common factors.

Factor $3$ out of $3$ .

$x = - \frac{3 \cdot 4}{3 (1)}$

Cancel the common factor.

$x = - \frac{3 \cdot 4}{3 \cdot 1}$

Rewrite the expression.

$x = - \frac{4}{1}$

Divide $4$ by $1$ .

$x = - 1 \cdot 4$

Multiply $- 1$ by $4$ .

$x = - 4$

Step 3

Evaluate $f (- 4)$ .

Replace the variable $x$ with $- 4$ in the expression.

$f (- 4) = 3 {(- 4)}^{2} + 24 (- 4) - 6$

Simplify the result.

Simplify each term.

Raise $- 4$ to the power of $2$ .

$f (- 4) = 3 \cdot 16 + 24 (- 4) - 6$

Multiply $3$ by $16$ .

$f (- 4) = 48 + 24 (- 4) - 6$

Multiply $24$ by $- 4$ .

$f (- 4) = 48 - 96 - 6$

Simplify by subtracting numbers.

Subtract $96$ from $48$ .

$f (- 4) = - 48 - 6$

Subtract $6$ from $- 48$ .

$f (- 4) = - 54$

The final answer is $- 54$ .

$- 54$

Step 4

Use the $x$ and $y$ values to find where the minimum occurs.

$(- 4, - 54)$

Step 5

Find the Maximum/Minimum Value 3x^2+24x-6

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