Find the Maximum/Minimum Value h(t)=100t-16t^2

$h (t) = 100 t - 16 t^{2}$

Step 1

The maximum of a quadratic function occurs at $x = - \frac{b}{2 a}$ . If $a$ is negative, the maximum value of the function is $f (- \frac{b}{2 a})$ .

$f_{max}$ $t = a t^{2} + b t + c$ occurs at $t = - \frac{b}{2 a}$

Step 2

Find the value of $t = - \frac{b}{2 a}$ .

Substitute in the values of $a$ and $b$ .

$t = - \frac{100}{2 (- 16)}$

Remove parentheses.

$t = - \frac{100}{2 (- 16)}$

Simplify $- \frac{100}{2 (- 16)}$ .

Cancel the common factor of $100$ and $2$ .

Factor $2$ out of $100$ .

$t = - \frac{2 \cdot 50}{2 \cdot - 16}$

Cancel the common factors.

Factor $2$ out of $2 \cdot - 16$ .

$t = - \frac{2 \cdot 50}{2 (- 16)}$

Cancel the common factor.

$t = - \frac{2 \cdot 50}{2 \cdot - 16}$

Rewrite the expression.

$t = - \frac{50}{- 16}$

Cancel the common factor of $50$ and $- 16$ .

Factor $2$ out of $50$ .

$t = - \frac{2 (25)}{- 16}$

Cancel the common factors.

Factor $2$ out of $- 16$ .

$t = - \frac{2 \cdot 25}{2 \cdot - 8}$

Cancel the common factor.

$t = - \frac{2 \cdot 25}{2 \cdot - 8}$

Rewrite the expression.

$t = - \frac{25}{- 8}$

Move the negative in front of the fraction.

$t = - - \frac{25}{8}$

Multiply $- - \frac{25}{8}$ .

Multiply $- 1$ by $- 1$ .

$t = 1 (\frac{25}{8})$

Multiply $\frac{25}{8}$ by $1$ .

$t = \frac{25}{8}$

Step 3

Evaluate $f (\frac{25}{8})$ .

Replace the variable $t$ with $\frac{25}{8}$ in the expression.

$h (\frac{25}{8}) = 100 (\frac{25}{8}) - 16 {(\frac{25}{8})}^{2}$

Simplify the result.

Simplify each term.

Cancel the common factor of $4$ .

Factor $4$ out of $100$ .

$h (\frac{25}{8}) = 4 (25) (\frac{25}{8}) - 16 {(\frac{25}{8})}^{2}$

Factor $4$ out of $8$ .

$h (\frac{25}{8}) = 4 \cdot (25 (\frac{25}{4 \cdot 2})) - 16 {(\frac{25}{8})}^{2}$

Cancel the common factor.

$h (\frac{25}{8}) = 4 \cdot (25 (\frac{25}{4 \cdot 2})) - 16 {(\frac{25}{8})}^{2}$

Rewrite the expression.

$h (\frac{25}{8}) = 25 (\frac{25}{2}) - 16 {(\frac{25}{8})}^{2}$

Combine $25$ and $\frac{25}{2}$ .

$h (\frac{25}{8}) = \frac{25 \cdot 25}{2} - 16 {(\frac{25}{8})}^{2}$

Multiply $25$ by $25$ .

$h (\frac{25}{8}) = \frac{625}{2} - 16 {(\frac{25}{8})}^{2}$

Apply the product rule to $\frac{25}{8}$ .

$h (\frac{25}{8}) = \frac{625}{2} - 16 \frac{25^{2}}{8^{2}}$

Raise $25$ to the power of $2$ .

$h (\frac{25}{8}) = \frac{625}{2} - 16 \frac{625}{8^{2}}$

Raise $8$ to the power of $2$ .

$h (\frac{25}{8}) = \frac{625}{2} - 16 (\frac{625}{64})$

Cancel the common factor of $16$ .

Factor $16$ out of $- 16$ .

$h (\frac{25}{8}) = \frac{625}{2} + 16 (- 1) (\frac{625}{64})$

Factor $16$ out of $64$ .

$h (\frac{25}{8}) = \frac{625}{2} + 16 \cdot (- 1 \frac{625}{16 \cdot 4})$

Cancel the common factor.

$h (\frac{25}{8}) = \frac{625}{2} + 16 \cdot (- 1 \frac{625}{16 \cdot 4})$

Rewrite the expression.

$h (\frac{25}{8}) = \frac{625}{2} - 1 (\frac{625}{4})$

Rewrite $- 1 (\frac{625}{4})$ as $- (\frac{625}{4})$ .

$h (\frac{25}{8}) = \frac{625}{2} - \frac{625}{4}$

To write $\frac{625}{2}$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$h (\frac{25}{8}) = \frac{625}{2} \cdot \frac{2}{2} - \frac{625}{4}$

Write each expression with a common denominator of $4$ , by multiplying each by an appropriate factor of $1$ .

Multiply $\frac{625}{2}$ by $\frac{2}{2}$ .

$h (\frac{25}{8}) = \frac{625 \cdot 2}{2 \cdot 2} - \frac{625}{4}$

Multiply $2$ by $2$ .

$h (\frac{25}{8}) = \frac{625 \cdot 2}{4} - \frac{625}{4}$

Combine the numerators over the common denominator.

$h (\frac{25}{8}) = \frac{625 \cdot 2 - 625}{4}$

Simplify the numerator.

Multiply $625$ by $2$ .

$h (\frac{25}{8}) = \frac{1250 - 625}{4}$

Subtract $625$ from $1250$ .

$h (\frac{25}{8}) = \frac{625}{4}$

The final answer is $\frac{625}{4}$ .

$\frac{625}{4}$

Step 4

Use the $x$ and $y$ values to find where the maximum occurs.

$(\frac{25}{8}, \frac{625}{4})$

Step 5

Find the Maximum/Minimum Value h(t)=100t-16t^2

Related Questions

Support LCMGCF.com by disabling your adblocker.