Find the Maximum Number of Real Roots 6x^3-47x^2+36x-7=0

$6 x^{3} - 47 x^{2} + 36 x - 7 = 0$

Step 1

Identify the exponents on the variables in each term, and add them together to find the degree of each term.

$6 x^{3} \to 3$

$- 47 x^{2} \to 2$

$36 x \to 1$

$- 7 \to 0$

Step 2

The largest exponent is the degree of the polynomial.

$3$

Step 3

The maximum number of possible roots is the degree of $6 x^{3} - 47 x^{2} + 36 x - 7$ .

$3$