Find the Mean 12.5 , 9.8 , 13.5 , 11.2 , 12.3 , 14.2 , 11.7 , 9.8 , 12.6 , 10.4

$12.5$ , $9.8$ , $13.5$ , $11.2$ , $12.3$ , $14.2$ , $11.7$ , $9.8$ , $12.6$ , $10.4$

Step 1

The mean of a set of numbers is the sum divided by the number of terms.

$\frac{12.5 + 9.8 + 13.5 + 11.2 + 12.3 + 14.2 + 11.7 + 9.8 + 12.6 + 10.4}{10}$

Step 2

Simplify the numerator.

Add $12.5$ and $9.8$ .

$\frac{22.3 + 13.5 + 11.2 + 12.3 + 14.2 + 11.7 + 9.8 + 12.6 + 10.4}{10}$

Add $22.3$ and $13.5$ .

$\frac{35.8 + 11.2 + 12.3 + 14.2 + 11.7 + 9.8 + 12.6 + 10.4}{10}$

Add $35.8$ and $11.2$ .

$\frac{47 + 12.3 + 14.2 + 11.7 + 9.8 + 12.6 + 10.4}{10}$

Add $47$ and $12.3$ .

$\frac{59.3 + 14.2 + 11.7 + 9.8 + 12.6 + 10.4}{10}$

Add $59.3$ and $14.2$ .

$\frac{73.5 + 11.7 + 9.8 + 12.6 + 10.4}{10}$

Add $73.5$ and $11.7$ .

$\frac{85.2 + 9.8 + 12.6 + 10.4}{10}$

Add $85.2$ and $9.8$ .

$\frac{95 + 12.6 + 10.4}{10}$

Add $95$ and $12.6$ .

$\frac{107.6 + 10.4}{10}$

Add $107.6$ and $10.4$ .

$\frac{118}{10}$

Step 3

Cancel the common factor of $118$ and $10$ .

Factor $2$ out of $118$ .

$\frac{2 (59)}{10}$

Cancel the common factors.

Factor $2$ out of $10$ .

$\frac{2 \cdot 59}{2 \cdot 5}$

Cancel the common factor.

$\frac{2 \cdot 59}{2 \cdot 5}$

Rewrite the expression.

$\frac{59}{5}$

Step 4

Divide.

$11.8$