Find the Mean 12 , 9 , 10 , 11 , 12 , 14 , 8 , 7 , 10 , 11 , 10 , 9

$12$ , $9$ , $10$ , $11$ , $12$ , $14$ , $8$ , $7$ , $10$ , $11$ , $10$ , $9$

Step 1

The mean of a set of numbers is the sum divided by the number of terms.

$\frac{12 + 9 + 10 + 11 + 12 + 14 + 8 + 7 + 10 + 11 + 10 + 9}{12}$

Step 2

Simplify the numerator.

Add $12$ and $9$ .

$\frac{21 + 10 + 11 + 12 + 14 + 8 + 7 + 10 + 11 + 10 + 9}{12}$

Add $21$ and $10$ .

$\frac{31 + 11 + 12 + 14 + 8 + 7 + 10 + 11 + 10 + 9}{12}$

Add $31$ and $11$ .

$\frac{42 + 12 + 14 + 8 + 7 + 10 + 11 + 10 + 9}{12}$

Add $42$ and $12$ .

$\frac{54 + 14 + 8 + 7 + 10 + 11 + 10 + 9}{12}$

Add $54$ and $14$ .

$\frac{68 + 8 + 7 + 10 + 11 + 10 + 9}{12}$

Add $68$ and $8$ .

$\frac{76 + 7 + 10 + 11 + 10 + 9}{12}$

Add $76$ and $7$ .

$\frac{83 + 10 + 11 + 10 + 9}{12}$

Add $83$ and $10$ .

$\frac{93 + 11 + 10 + 9}{12}$

Add $93$ and $11$ .

$\frac{104 + 10 + 9}{12}$

Add $104$ and $10$ .

$\frac{114 + 9}{12}$

Add $114$ and $9$ .

$\frac{123}{12}$

Step 3

Cancel the common factor of $123$ and $12$ .

Factor $3$ out of $123$ .

$\frac{3 (41)}{12}$

Cancel the common factors.

Factor $3$ out of $12$ .

$\frac{3 \cdot 41}{3 \cdot 4}$

Cancel the common factor.

$\frac{3 \cdot 41}{3 \cdot 4}$

Rewrite the expression.

$\frac{41}{4}$

Step 4

Divide.

$10.25$

Step 5

The mean should be rounded to one more decimal place than the original data. If the original data were mixed, round to one decimal place more than the least precise.

$10.3$

Find the Mean 12 , 9 , 10 , 11 , 12 , 14 , 8 , 7 , 10 , 11 , 10 , 9

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