Find the Mean 23 , 50 , 49 , 48 , 49 , 32 , 37 , 40 , 41 , 42 , 41 , 41 , 43

$23$ , $50$ , $49$ , $48$ , $49$ , $32$ , $37$ , $40$ , $41$ , $42$ , $41$ , $41$ , $43$

Step 1

The mean of a set of numbers is the sum divided by the number of terms.

$\frac{23 + 50 + 49 + 48 + 49 + 32 + 37 + 40 + 41 + 42 + 41 + 41 + 43}{13}$

Step 2

Simplify the numerator.

Add $23$ and $50$ .

$\frac{73 + 49 + 48 + 49 + 32 + 37 + 40 + 41 + 42 + 41 + 41 + 43}{13}$

Add $73$ and $49$ .

$\frac{122 + 48 + 49 + 32 + 37 + 40 + 41 + 42 + 41 + 41 + 43}{13}$

Add $122$ and $48$ .

$\frac{170 + 49 + 32 + 37 + 40 + 41 + 42 + 41 + 41 + 43}{13}$

Add $170$ and $49$ .

$\frac{219 + 32 + 37 + 40 + 41 + 42 + 41 + 41 + 43}{13}$

Add $219$ and $32$ .

$\frac{251 + 37 + 40 + 41 + 42 + 41 + 41 + 43}{13}$

Add $251$ and $37$ .

$\frac{288 + 40 + 41 + 42 + 41 + 41 + 43}{13}$

Add $288$ and $40$ .

$\frac{328 + 41 + 42 + 41 + 41 + 43}{13}$

Add $328$ and $41$ .

$\frac{369 + 42 + 41 + 41 + 43}{13}$

Add $369$ and $42$ .

$\frac{411 + 41 + 41 + 43}{13}$

Add $411$ and $41$ .

$\frac{452 + 41 + 43}{13}$

Add $452$ and $41$ .

$\frac{493 + 43}{13}$

Add $493$ and $43$ .

$\frac{536}{13}$

Step 3

Divide.

$41.23076923$

Step 4

The mean should be rounded to one more decimal place than the original data. If the original data were mixed, round to one decimal place more than the least precise.

$41.2$

Find the Mean 23 , 50 , 49 , 48 , 49 , 32 , 37 , 40 , 41 , 42 , 41 , 41 , 43

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