Find the Mean 8 , 1 , 2 , 6 , 1 , 4

$8$ , $1$ , $2$ , $6$ , $1$ , $4$

Step 1

The mean of a set of numbers is the sum divided by the number of terms.

$\frac{8 + 1 + 2 + 6 + 1 + 4}{6}$

Step 2

Simplify the numerator.

Add $8$ and $1$ .

$\frac{9 + 2 + 6 + 1 + 4}{6}$

Add $9$ and $2$ .

$\frac{11 + 6 + 1 + 4}{6}$

Add $11$ and $6$ .

$\frac{17 + 1 + 4}{6}$

Add $17$ and $1$ .

$\frac{18 + 4}{6}$

Add $18$ and $4$ .

$\frac{22}{6}$

Step 3

Cancel the common factor of $22$ and $6$ .

Factor $2$ out of $22$ .

$\frac{2 (11)}{6}$

Cancel the common factors.

Factor $2$ out of $6$ .

$\frac{2 \cdot 11}{2 \cdot 3}$

Cancel the common factor.

$\frac{2 \cdot 11}{2 \cdot 3}$

Rewrite the expression.

$\frac{11}{3}$

Step 4

Divide.

$3.\overline{6}$

Step 5

The mean should be rounded to one more decimal place than the original data. If the original data were mixed, round to one decimal place more than the least precise.

$3.7$

Find the Mean 8 , 1 , 2 , 6 , 1 , 4

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