Find the Mean 9 , 8 , 6 , 7 , 8 , 5 , 6 , 9 , 7 , 7

$9$ , $8$ , $6$ , $7$ , $8$ , $5$ , $6$ , $9$ , $7$ , $7$

Step 1

The mean of a set of numbers is the sum divided by the number of terms.

$\frac{9 + 8 + 6 + 7 + 8 + 5 + 6 + 9 + 7 + 7}{10}$

Step 2

Simplify the numerator.

Add $9$ and $8$ .

$\frac{17 + 6 + 7 + 8 + 5 + 6 + 9 + 7 + 7}{10}$

Add $17$ and $6$ .

$\frac{23 + 7 + 8 + 5 + 6 + 9 + 7 + 7}{10}$

Add $23$ and $7$ .

$\frac{30 + 8 + 5 + 6 + 9 + 7 + 7}{10}$

Add $30$ and $8$ .

$\frac{38 + 5 + 6 + 9 + 7 + 7}{10}$

Add $38$ and $5$ .

$\frac{43 + 6 + 9 + 7 + 7}{10}$

Add $43$ and $6$ .

$\frac{49 + 9 + 7 + 7}{10}$

Add $49$ and $9$ .

$\frac{58 + 7 + 7}{10}$

Add $58$ and $7$ .

$\frac{65 + 7}{10}$

Add $65$ and $7$ .

$\frac{72}{10}$

Step 3

Cancel the common factor of $72$ and $10$ .

Factor $2$ out of $72$ .

$\frac{2 (36)}{10}$

Cancel the common factors.

Factor $2$ out of $10$ .

$\frac{2 \cdot 36}{2 \cdot 5}$

Cancel the common factor.

$\frac{2 \cdot 36}{2 \cdot 5}$

Rewrite the expression.

$\frac{36}{5}$

Step 4

Divide.

$7.2$