Find the Median 56 , 32 , 48 , 52 , 51 , 53 , 48 , 38 , 35 , 42 , 40 , 46 , 54 , 50

$56$ , $32$ , $48$ , $52$ , $51$ , $53$ , $48$ , $38$ , $35$ , $42$ , $40$ , $46$ , $54$ , $50$

Step 1

Arrange the terms in ascending order.

$32, 35, 38, 40, 42, 46, 48, 48, 50, 51, 52, 53, 54, 56$

Step 2

The median is the middle term in the arranged data set. In the case of an even number of terms, the median is the average of the two middle terms.

$\frac{48 + 48}{2}$

Step 3

Remove parentheses.

$\frac{48 + 48}{2}$

Step 4

Cancel the common factor of $48 + 48$ and $2$ .

Factor $2$ out of $48$ .

$\frac{2 \cdot 24 + 48}{2}$

Factor $2$ out of $48$ .

$\frac{2 \cdot 24 + 2 \cdot 24}{2}$

Factor $2$ out of $2 \cdot 24 + 2 \cdot 24$ .

$\frac{2 \cdot (24 + 24)}{2}$

Cancel the common factors.

Factor $2$ out of $2$ .

$\frac{2 \cdot (24 + 24)}{2 (1)}$

Cancel the common factor.

$\frac{2 \cdot (24 + 24)}{2 \cdot 1}$

Rewrite the expression.

$\frac{24 + 24}{1}$

Divide $24 + 24$ by $1$ .

$24 + 24$

Step 5

Add $24$ and $24$ .

$48$

Step 6

Convert the median $48$ to decimal.

$48$