Find the Median 8 , 16 , 24 , 24 , 32 , 32 , 32 , 48 , 48 , 48 , 48 , 64

$8$ , $16$ , $24$ , $24$ , $32$ , $32$ , $32$ , $48$ , $48$ , $48$ , $48$ , $64$

Step 1

Arrange the terms in ascending order.

$8, 16, 24, 24, 32, 32, 32, 48, 48, 48, 48, 64$

Step 2

The median is the middle term in the arranged data set. In the case of an even number of terms, the median is the average of the two middle terms.

$\frac{32 + 32}{2}$

Step 3

Remove parentheses.

$\frac{32 + 32}{2}$

Step 4

Cancel the common factor of $32 + 32$ and $2$ .

Factor $2$ out of $32$ .

$\frac{2 \cdot 16 + 32}{2}$

Factor $2$ out of $32$ .

$\frac{2 \cdot 16 + 2 \cdot 16}{2}$

Factor $2$ out of $2 \cdot 16 + 2 \cdot 16$ .

$\frac{2 \cdot (16 + 16)}{2}$

Cancel the common factors.

Factor $2$ out of $2$ .

$\frac{2 \cdot (16 + 16)}{2 (1)}$

Cancel the common factor.

$\frac{2 \cdot (16 + 16)}{2 \cdot 1}$

Rewrite the expression.

$\frac{16 + 16}{1}$

Divide $16 + 16$ by $1$ .

$16 + 16$

Step 5

Add $16$ and $16$ .

$32$

Step 6

Convert the median $32$ to decimal.

$32$