Find the Median 88 , 79 , 86 , 93 , 76 , 80 , 82 , 72 , 95 , 79

$88$ , $79$ , $86$ , $93$ , $76$ , $80$ , $82$ , $72$ , $95$ , $79$

Step 1

Arrange the terms in ascending order.

$72, 76, 79, 79, 80, 82, 86, 88, 93, 95$

Step 2

The median is the middle term in the arranged data set. In the case of an even number of terms, the median is the average of the two middle terms.

$\frac{80 + 82}{2}$

Step 3

Remove parentheses.

$\frac{80 + 82}{2}$

Step 4

Cancel the common factor of $80 + 82$ and $2$ .

Factor $2$ out of $80$ .

$\frac{2 \cdot 40 + 82}{2}$

Factor $2$ out of $82$ .

$\frac{2 \cdot 40 + 2 \cdot 41}{2}$

Factor $2$ out of $2 \cdot 40 + 2 \cdot 41$ .

$\frac{2 \cdot (40 + 41)}{2}$

Cancel the common factors.

Factor $2$ out of $2$ .

$\frac{2 \cdot (40 + 41)}{2 (1)}$

Cancel the common factor.

$\frac{2 \cdot (40 + 41)}{2 \cdot 1}$

Rewrite the expression.

$\frac{40 + 41}{1}$

Divide $40 + 41$ by $1$ .

$40 + 41$

Step 5

Add $40$ and $41$ .

$81$

Step 6

Convert the median $81$ to decimal.

$81$