Find the Midpoint (12,6) , (3,6)

$(12, 6)$ , $(3, 6)$

Step 1

Use the midpoint formula to find the midpoint of the line segment.

$(\frac{x_{1} + x_{2}}{2}, \frac{y_{1} + y_{2}}{2})$

Step 2

Substitute in the values for $(x_{1}, y_{1})$ and $(x_{2}, y_{2})$ .

$(\frac{12 + 3}{2}, \frac{6 + 6}{2})$

Step 3

Add $12$ and $3$ .

$(\frac{15}{2}, \frac{6 + 6}{2})$

Step 4

Cancel the common factor of $6 + 6$ and $2$ .

Factor $2$ out of $6$ .

$(\frac{15}{2}, \frac{2 \cdot 3 + 6}{2})$

Factor $2$ out of $6$ .

$(\frac{15}{2}, \frac{2 \cdot 3 + 2 \cdot 3}{2})$

Factor $2$ out of $2 \cdot 3 + 2 \cdot 3$ .

$(\frac{15}{2}, \frac{2 \cdot (3 + 3)}{2})$

Cancel the common factors.

Factor $2$ out of $2$ .

$(\frac{15}{2}, \frac{2 \cdot (3 + 3)}{2 (1)})$

Cancel the common factor.

$(\frac{15}{2}, \frac{2 \cdot (3 + 3)}{2 \cdot 1})$

Rewrite the expression.

$(\frac{15}{2}, \frac{3 + 3}{1})$

Divide $3 + 3$ by $1$ .

$(\frac{15}{2}, 3 + 3)$

Step 5

Add $3$ and $3$ .

$(\frac{15}{2}, 6)$

Step 6