Find the Midpoint (13,-14) and (-13,10)

$(13, - 14)$ and $(- 13, 10)$

Use the midpoint formula to find the midpoint of the line segment.

$(\frac{x_{1} + x_{2}}{2}, \frac{y_{1} + y_{2}}{2})$

Substitute in the values for $(x_{1}, y_{1})$ and $(x_{2}, y_{2})$ .

$(\frac{13 - 13}{2}, \frac{- 14 + 10}{2})$

Subtract $13$ from $13$ .

$(\frac{0}{2}, \frac{- 14 + 10}{2})$

Divide $0$ by $2$ .

$(0, \frac{- 14 + 10}{2})$

Cancel the common factor of $- 14 + 10$ and $2$ .

Factor $2$ out of $- 14$ .

$(0, \frac{2 \cdot - 7 + 10}{2})$

Factor $2$ out of $10$ .

$(0, \frac{2 \cdot - 7 + 2 \cdot 5}{2})$

Factor $2$ out of $2 \cdot - 7 + 2 \cdot 5$ .

$(0, \frac{2 \cdot (- 7 + 5)}{2})$

Cancel the common factors.

Factor $2$ out of $2$ .

$(0, \frac{2 \cdot (- 7 + 5)}{2 (1)})$

Cancel the common factor.

$(0, \frac{2 \cdot (- 7 + 5)}{2 \cdot 1})$

Rewrite the expression.

$(0, \frac{- 7 + 5}{1})$

Divide $- 7 + 5$ by $1$ .

$(0, - 7 + 5)$

Add $- 7$ and $5$ .

$(0, - 2)$