Find the Midpoint (13,8) , (-6,-6)

$(13, 8)$ , $(- 6, - 6)$

Step 1

Use the midpoint formula to find the midpoint of the line segment.

$(\frac{x_{1} + x_{2}}{2}, \frac{y_{1} + y_{2}}{2})$

Step 2

Substitute in the values for $(x_{1}, y_{1})$ and $(x_{2}, y_{2})$ .

$(\frac{13 - 6}{2}, \frac{8 - 6}{2})$

Step 3

Subtract $6$ from $13$ .

$(\frac{7}{2}, \frac{8 - 6}{2})$

Step 4

Cancel the common factor of $8 - 6$ and $2$ .

Factor $2$ out of $8$ .

$(\frac{7}{2}, \frac{2 \cdot 4 - 6}{2})$

Factor $2$ out of $- 6$ .

$(\frac{7}{2}, \frac{2 \cdot 4 + 2 \cdot - 3}{2})$

Factor $2$ out of $2 \cdot 4 + 2 \cdot - 3$ .

$(\frac{7}{2}, \frac{2 \cdot (4 - 3)}{2})$

Cancel the common factors.

Factor $2$ out of $2$ .

$(\frac{7}{2}, \frac{2 \cdot (4 - 3)}{2 (1)})$

Cancel the common factor.

$(\frac{7}{2}, \frac{2 \cdot (4 - 3)}{2 \cdot 1})$

Rewrite the expression.

$(\frac{7}{2}, \frac{4 - 3}{1})$

Divide $4 - 3$ by $1$ .

$(\frac{7}{2}, 4 - 3)$

Step 5

Subtract $3$ from $4$ .

$(\frac{7}{2}, 1)$

Step 6