Find the Midpoint (-3,-4) , (6,-8)

$(- 3, - 4)$ , $(6, - 8)$

Use the midpoint formula to find the midpoint of the line segment.

$(\frac{x_{1} + x_{2}}{2}, \frac{y_{1} + y_{2}}{2})$

Substitute in the values for $(x_{1}, y_{1})$ and $(x_{2}, y_{2})$ .

$(\frac{- 3 + 6}{2}, \frac{- 4 - 8}{2})$

Add $- 3$ and $6$ .

$(\frac{3}{2}, \frac{- 4 - 8}{2})$

Cancel the common factor of $- 4 - 8$ and $2$ .

Factor $2$ out of $- 4$ .

$(\frac{3}{2}, \frac{2 \cdot - 2 - 8}{2})$

Factor $2$ out of $- 8$ .

$(\frac{3}{2}, \frac{2 \cdot - 2 + 2 \cdot - 4}{2})$

Factor $2$ out of $2 \cdot - 2 + 2 \cdot - 4$ .

$(\frac{3}{2}, \frac{2 \cdot (- 2 - 4)}{2})$

Cancel the common factors.

Factor $2$ out of $2$ .

$(\frac{3}{2}, \frac{2 \cdot (- 2 - 4)}{2 (1)})$

Cancel the common factor.

$(\frac{3}{2}, \frac{2 \cdot (- 2 - 4)}{2 \cdot 1})$

Rewrite the expression.

$(\frac{3}{2}, \frac{- 2 - 4}{1})$

Divide $- 2 - 4$ by $1$ .

$(\frac{3}{2}, - 2 - 4)$

Subtract $4$ from $- 2$ .

$(\frac{3}{2}, - 6)$