Find the Midpoint (-3,6) and (3,0)

$(- 3, 6)$ and $(3, 0)$

Use the midpoint formula to find the midpoint of the line segment.

$(\frac{x_{1} + x_{2}}{2}, \frac{y_{1} + y_{2}}{2})$

Substitute in the values for $(x_{1}, y_{1})$ and $(x_{2}, y_{2})$ .

$(\frac{- 3 + 3}{2}, \frac{6 + 0}{2})$

Add $- 3$ and $3$ .

$(\frac{0}{2}, \frac{6 + 0}{2})$

Divide $0$ by $2$ .

$(0, \frac{6 + 0}{2})$

Cancel the common factor of $6 + 0$ and $2$ .

Factor $2$ out of $6$ .

$(0, \frac{2 \cdot 3 + 0}{2})$

Factor $2$ out of $0$ .

$(0, \frac{2 \cdot 3 + 2 \cdot 0}{2})$

Factor $2$ out of $2 \cdot 3 + 2 \cdot 0$ .

$(0, \frac{2 \cdot (3 + 0)}{2})$

Cancel the common factors.

Factor $2$ out of $2$ .

$(0, \frac{2 \cdot (3 + 0)}{2 (1)})$

Cancel the common factor.

$(0, \frac{2 \cdot (3 + 0)}{2 \cdot 1})$

Rewrite the expression.

$(0, \frac{3 + 0}{1})$

Divide $3 + 0$ by $1$ .

$(0, 3 + 0)$

Add $3$ and $0$ .

$(0, 3)$