Find the Midpoint (-4,8) , (6,7)

$(- 4, 8)$ , $(6, 7)$

Use the midpoint formula to find the midpoint of the line segment.

$(\frac{x_{1} + x_{2}}{2}, \frac{y_{1} + y_{2}}{2})$

Substitute in the values for $(x_{1}, y_{1})$ and $(x_{2}, y_{2})$ .

$(\frac{- 4 + 6}{2}, \frac{8 + 7}{2})$

Cancel the common factor of $- 4 + 6$ and $2$ .

Factor $2$ out of $- 4$ .

$(\frac{2 \cdot - 2 + 6}{2}, \frac{8 + 7}{2})$

Factor $2$ out of $6$ .

$(\frac{2 \cdot - 2 + 2 \cdot 3}{2}, \frac{8 + 7}{2})$

Factor $2$ out of $2 \cdot - 2 + 2 \cdot 3$ .

$(\frac{2 \cdot (- 2 + 3)}{2}, \frac{8 + 7}{2})$

Cancel the common factors.

Factor $2$ out of $2$ .

$(\frac{2 \cdot (- 2 + 3)}{2 (1)}, \frac{8 + 7}{2})$

Cancel the common factor.

$(\frac{2 \cdot (- 2 + 3)}{2 \cdot 1}, \frac{8 + 7}{2})$

Rewrite the expression.

$(\frac{- 2 + 3}{1}, \frac{8 + 7}{2})$

Divide $- 2 + 3$ by $1$ .

$(- 2 + 3, \frac{8 + 7}{2})$

Add $- 2$ and $3$ .

$(1, \frac{8 + 7}{2})$

Add $8$ and $7$ .

$(1, \frac{15}{2})$