Find the Midpoint (-6,4) and (-1,-6)

$(- 6, 4)$ and $(- 1, - 6)$

Use the midpoint formula to find the midpoint of the line segment.

$(\frac{x_{1} + x_{2}}{2}, \frac{y_{1} + y_{2}}{2})$

Substitute in the values for $(x_{1}, y_{1})$ and $(x_{2}, y_{2})$ .

$(\frac{- 6 - 1}{2}, \frac{4 - 6}{2})$

Subtract $1$ from $- 6$ .

$(\frac{- 7}{2}, \frac{4 - 6}{2})$

Move the negative in front of the fraction.

$(- \frac{7}{2}, \frac{4 - 6}{2})$

Cancel the common factor of $4 - 6$ and $2$ .

Factor $2$ out of $4$ .

$(- \frac{7}{2}, \frac{2 \cdot 2 - 6}{2})$

Factor $2$ out of $- 6$ .

$(- \frac{7}{2}, \frac{2 \cdot 2 + 2 \cdot - 3}{2})$

Factor $2$ out of $2 \cdot 2 + 2 \cdot - 3$ .

$(- \frac{7}{2}, \frac{2 \cdot (2 - 3)}{2})$

Cancel the common factors.

Factor $2$ out of $2$ .

$(- \frac{7}{2}, \frac{2 \cdot (2 - 3)}{2 (1)})$

Cancel the common factor.

$(- \frac{7}{2}, \frac{2 \cdot (2 - 3)}{2 \cdot 1})$

Rewrite the expression.

$(- \frac{7}{2}, \frac{2 - 3}{1})$

Divide $2 - 3$ by $1$ .

$(- \frac{7}{2}, 2 - 3)$

Subtract $3$ from $2$ .

$(- \frac{7}{2}, - 1)$