Find the Midpoint (7,-2) and (1,-10)

$(7, - 2)$ and $(1, - 10)$

Use the midpoint formula to find the midpoint of the line segment.

$(\frac{x_{1} + x_{2}}{2}, \frac{y_{1} + y_{2}}{2})$

Substitute in the values for $(x_{1}, y_{1})$ and $(x_{2}, y_{2})$ .

$(\frac{7 + 1}{2}, \frac{- 2 - 10}{2})$

Add $7$ and $1$ .

$(\frac{8}{2}, \frac{- 2 - 10}{2})$

Divide $8$ by $2$ .

$(4, \frac{- 2 - 10}{2})$

Cancel the common factor of $- 2 - 10$ and $2$ .

Factor $2$ out of $- 2$ .

$(4, \frac{2 \cdot - 1 - 10}{2})$

Factor $2$ out of $- 10$ .

$(4, \frac{2 \cdot - 1 + 2 \cdot - 5}{2})$

Factor $2$ out of $2 \cdot - 1 + 2 \cdot - 5$ .

$(4, \frac{2 \cdot (- 1 - 5)}{2})$

Cancel the common factors.

Factor $2$ out of $2$ .

$(4, \frac{2 \cdot (- 1 - 5)}{2 (1)})$

Cancel the common factor.

$(4, \frac{2 \cdot (- 1 - 5)}{2 \cdot 1})$

Rewrite the expression.

$(4, \frac{- 1 - 5}{1})$

Divide $- 1 - 5$ by $1$ .

$(4, - 1 - 5)$

Subtract $5$ from $- 1$ .

$(4, - 6)$