Find the Midpoint (-7,-6) , (1,-2)

$(- 7, - 6)$ , $(1, - 2)$

Use the midpoint formula to find the midpoint of the line segment.

$(\frac{x_{1} + x_{2}}{2}, \frac{y_{1} + y_{2}}{2})$

Substitute in the values for $(x_{1}, y_{1})$ and $(x_{2}, y_{2})$ .

$(\frac{- 7 + 1}{2}, \frac{- 6 - 2}{2})$

Add $- 7$ and $1$ .

$(\frac{- 6}{2}, \frac{- 6 - 2}{2})$

Divide $- 6$ by $2$ .

$(- 3, \frac{- 6 - 2}{2})$

Cancel the common factor of $- 6 - 2$ and $2$ .

Factor $2$ out of $- 6$ .

$(- 3, \frac{2 \cdot - 3 - 2}{2})$

Factor $2$ out of $- 2$ .

$(- 3, \frac{2 \cdot - 3 + 2 \cdot - 1}{2})$

Factor $2$ out of $2 \cdot - 3 + 2 \cdot - 1$ .

$(- 3, \frac{2 \cdot (- 3 - 1)}{2})$

Cancel the common factors.

Factor $2$ out of $2$ .

$(- 3, \frac{2 \cdot (- 3 - 1)}{2 (1)})$

Cancel the common factor.

$(- 3, \frac{2 \cdot (- 3 - 1)}{2 \cdot 1})$

Rewrite the expression.

$(- 3, \frac{- 3 - 1}{1})$

Divide $- 3 - 1$ by $1$ .

$(- 3, - 3 - 1)$

Subtract $1$ from $- 3$ .

$(- 3, - 4)$