Find the Midpoint (8,-3) and (2,-10)

$(8, - 3)$ and $(2, - 10)$

Use the midpoint formula to find the midpoint of the line segment.

$(\frac{x_{1} + x_{2}}{2}, \frac{y_{1} + y_{2}}{2})$

Substitute in the values for $(x_{1}, y_{1})$ and $(x_{2}, y_{2})$ .

$(\frac{8 + 2}{2}, \frac{- 3 - 10}{2})$

Cancel the common factor of $8 + 2$ and $2$ .

Factor $2$ out of $8$ .

$(\frac{2 \cdot 4 + 2}{2}, \frac{- 3 - 10}{2})$

Factor $2$ out of $2$ .

$(\frac{2 \cdot 4 + 2 \cdot 1}{2}, \frac{- 3 - 10}{2})$

Factor $2$ out of $2 \cdot 4 + 2 \cdot 1$ .

$(\frac{2 \cdot (4 + 1)}{2}, \frac{- 3 - 10}{2})$

Cancel the common factors.

Factor $2$ out of $2$ .

$(\frac{2 \cdot (4 + 1)}{2 (1)}, \frac{- 3 - 10}{2})$

Cancel the common factor.

$(\frac{2 \cdot (4 + 1)}{2 \cdot 1}, \frac{- 3 - 10}{2})$

Rewrite the expression.

$(\frac{4 + 1}{1}, \frac{- 3 - 10}{2})$

Divide $4 + 1$ by $1$ .

$(4 + 1, \frac{- 3 - 10}{2})$

Add $4$ and $1$ .

$(5, \frac{- 3 - 10}{2})$

Subtract $10$ from $- 3$ .

$(5, \frac{- 13}{2})$

Move the negative in front of the fraction.

$(5, - \frac{13}{2})$