Find the Midpoint (9,8) and (3,2)

$(9, 8)$ and $(3, 2)$

Step 1

Use the midpoint formula to find the midpoint of the line segment.

$(\frac{x_{1} + x_{2}}{2}, \frac{y_{1} + y_{2}}{2})$

Step 2

Substitute in the values for $(x_{1}, y_{1})$ and $(x_{2}, y_{2})$ .

$(\frac{9 + 3}{2}, \frac{8 + 2}{2})$

Step 3

Add $9$ and $3$ .

$(\frac{12}{2}, \frac{8 + 2}{2})$

Step 4

Divide $12$ by $2$ .

$(6, \frac{8 + 2}{2})$

Step 5

Cancel the common factor of $8 + 2$ and $2$ .

Factor $2$ out of $8$ .

$(6, \frac{2 \cdot 4 + 2}{2})$

Factor $2$ out of $2$ .

$(6, \frac{2 \cdot 4 + 2 \cdot 1}{2})$

Factor $2$ out of $2 \cdot 4 + 2 \cdot 1$ .

$(6, \frac{2 \cdot (4 + 1)}{2})$

Cancel the common factors.

Factor $2$ out of $2$ .

$(6, \frac{2 \cdot (4 + 1)}{2 (1)})$

Cancel the common factor.

$(6, \frac{2 \cdot (4 + 1)}{2 \cdot 1})$

Rewrite the expression.

$(6, \frac{4 + 1}{1})$

Divide $4 + 1$ by $1$ .

$(6, 4 + 1)$

Step 6

Add $4$ and $1$ .

$(6, 5)$

Step 7