Find the Midpoint (-9,8) and (-4,-2)

$(- 9, 8)$ and $(- 4, - 2)$

Use the midpoint formula to find the midpoint of the line segment.

$(\frac{x_{1} + x_{2}}{2}, \frac{y_{1} + y_{2}}{2})$

Substitute in the values for $(x_{1}, y_{1})$ and $(x_{2}, y_{2})$ .

$(\frac{- 9 - 4}{2}, \frac{8 - 2}{2})$

Subtract $4$ from $- 9$ .

$(\frac{- 13}{2}, \frac{8 - 2}{2})$

Move the negative in front of the fraction.

$(- \frac{13}{2}, \frac{8 - 2}{2})$

Cancel the common factor of $8 - 2$ and $2$ .

Factor $2$ out of $8$ .

$(- \frac{13}{2}, \frac{2 \cdot 4 - 2}{2})$

Factor $2$ out of $- 2$ .

$(- \frac{13}{2}, \frac{2 \cdot 4 + 2 \cdot - 1}{2})$

Factor $2$ out of $2 \cdot 4 + 2 \cdot - 1$ .

$(- \frac{13}{2}, \frac{2 \cdot (4 - 1)}{2})$

Cancel the common factors.

Factor $2$ out of $2$ .

$(- \frac{13}{2}, \frac{2 \cdot (4 - 1)}{2 (1)})$

Cancel the common factor.

$(- \frac{13}{2}, \frac{2 \cdot (4 - 1)}{2 \cdot 1})$

Rewrite the expression.

$(- \frac{13}{2}, \frac{4 - 1}{1})$

Divide $4 - 1$ by $1$ .

$(- \frac{13}{2}, 4 - 1)$

Subtract $1$ from $4$ .

$(- \frac{13}{2}, 3)$