Find the Other Trig Values in Quadrant III cot(theta)=12/5

$\cot (θ) = \frac{12}{5}$

Use the definition of cotangent to find the known sides of the unit circle right triangle. The quadrant determines the sign on each of the values.

$\cot (θ) = \frac{adjacent}{opposite}$

Find the hypotenuse of the unit circle triangle. Since the opposite and adjacent sides are known, use the Pythagorean theorem to find the remaining side.

$Hypotenuse = \sqrt{{opposite}^{2} + {adjacent}^{2}}$

Replace the known values in the equation.

$Hypotenuse = \sqrt{{(- 5)}^{2} + {(- 12)}^{2}}$

Simplify inside the radical.

Raise $- 5$ to the power of $2$ .

Hypotenuse $= \sqrt{25 + {(- 12)}^{2}}$

Raise $- 12$ to the power of $2$ .

Hypotenuse $= \sqrt{25 + 144}$

Add $25$ and $144$ .

Hypotenuse $= \sqrt{169}$

Rewrite $169$ as $13^{2}$ .

Hypotenuse $= \sqrt{13^{2}}$

Pull terms out from under the radical, assuming positive real numbers.

Hypotenuse $= 13$

Find the value of sine.

Use the definition of sine to find the value of $\sin (θ)$ .

$\sin (θ) = \frac{opp}{hyp}$

Substitute in the known values.

$\sin (θ) = \frac{- 5}{13}$

Move the negative in front of the fraction.

$\sin (θ) = - \frac{5}{13}$

Find the value of cosine.

Use the definition of cosine to find the value of $\cos (θ)$ .

$\cos (θ) = \frac{adj}{hyp}$

Substitute in the known values.

$\cos (θ) = \frac{- 12}{13}$

Move the negative in front of the fraction.

$\cos (θ) = - \frac{12}{13}$

Find the value of tangent.

Use the definition of tangent to find the value of $\tan (θ)$ .

$\tan (θ) = \frac{opp}{adj}$

Substitute in the known values.

$\tan (θ) = \frac{- 5}{- 12}$

Dividing two negative values results in a positive value.

$\tan (θ) = \frac{5}{12}$

Find the value of secant.

Use the definition of secant to find the value of $\sec (θ)$ .

$\sec (θ) = \frac{hyp}{adj}$

Substitute in the known values.

$\sec (θ) = \frac{13}{- 12}$

Move the negative in front of the fraction.

$\sec (θ) = - \frac{13}{12}$

Find the value of cosecant.

Use the definition of cosecant to find the value of $\csc (θ)$ .

$\csc (θ) = \frac{hyp}{opp}$

Substitute in the known values.

$\csc (θ) = \frac{13}{- 5}$

Move the negative in front of the fraction.

$\csc (θ) = - \frac{13}{5}$

This is the solution to each trig value.

$\sin (θ) = - \frac{5}{13}$

$\cos (θ) = - \frac{12}{13}$

$\tan (θ) = \frac{5}{12}$

$\cot (θ) = \frac{12}{5}$

$\sec (θ) = - \frac{13}{12}$

$\csc (θ) = - \frac{13}{5}$

Find the Other Trig Values in Quadrant III cot(theta)=12/5

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