Find the Other Trig Values in Quadrant III cot(theta)=2/3

$\cot (θ) = \frac{2}{3}$

Use the definition of cotangent to find the known sides of the unit circle right triangle. The quadrant determines the sign on each of the values.

$\cot (θ) = \frac{adjacent}{opposite}$

Find the hypotenuse of the unit circle triangle. Since the opposite and adjacent sides are known, use the Pythagorean theorem to find the remaining side.

$Hypotenuse = \sqrt{{opposite}^{2} + {adjacent}^{2}}$

Replace the known values in the equation.

$Hypotenuse = \sqrt{{(- 3)}^{2} + {(- 2)}^{2}}$

Simplify inside the radical.

Raise $- 3$ to the power of $2$ .

Hypotenuse $= \sqrt{9 + {(- 2)}^{2}}$

Raise $- 2$ to the power of $2$ .

Hypotenuse $= \sqrt{9 + 4}$

Add $9$ and $4$ .

Hypotenuse $= \sqrt{13}$

Find the value of sine.

Use the definition of sine to find the value of $\sin (θ)$ .

$\sin (θ) = \frac{opp}{hyp}$

Substitute in the known values.

$\sin (θ) = \frac{- 3}{\sqrt{13}}$

Simplify the value of $\sin (θ)$ .

Move the negative in front of the fraction.

$\sin (θ) = - \frac{3}{\sqrt{13}}$

Multiply $\frac{3}{\sqrt{13}}$ by $\frac{\sqrt{13}}{\sqrt{13}}$ .

$\sin (θ) = - (\frac{3}{\sqrt{13}} \cdot \frac{\sqrt{13}}{\sqrt{13}})$

Combine and simplify the denominator.

Multiply $\frac{3}{\sqrt{13}}$ by $\frac{\sqrt{13}}{\sqrt{13}}$ .

$\sin (θ) = - \frac{3 \sqrt{13}}{\sqrt{13} \sqrt{13}}$

Raise $\sqrt{13}$ to the power of $1$ .

$\sin (θ) = - \frac{3 \sqrt{13}}{\sqrt{13} \sqrt{13}}$

Raise $\sqrt{13}$ to the power of $1$ .

$\sin (θ) = - \frac{3 \sqrt{13}}{\sqrt{13} \sqrt{13}}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\sin (θ) = - \frac{3 \sqrt{13}}{{\sqrt{13}}^{1 + 1}}$

Add $1$ and $1$ .

$\sin (θ) = - \frac{3 \sqrt{13}}{{\sqrt{13}}^{2}}$

Rewrite ${\sqrt{13}}^{2}$ as $13$ .

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{13}$ as $13^{\frac{1}{2}}$ .

$\sin (θ) = - \frac{3 \sqrt{13}}{{(13^{\frac{1}{2}})}^{2}}$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\sin (θ) = - \frac{3 \sqrt{13}}{13^{\frac{1}{2} \cdot 2}}$

Combine $\frac{1}{2}$ and $2$ .

$\sin (θ) = - \frac{3 \sqrt{13}}{13^{\frac{2}{2}}}$

Cancel the common factor of $2$ .

Cancel the common factor.

$\sin (θ) = - \frac{3 \sqrt{13}}{13^{\frac{2}{2}}}$

Rewrite the expression.

$\sin (θ) = - \frac{3 \sqrt{13}}{13}$

Evaluate the exponent.

$\sin (θ) = - \frac{3 \sqrt{13}}{13}$

Find the value of cosine.

Use the definition of cosine to find the value of $\cos (θ)$ .

$\cos (θ) = \frac{adj}{hyp}$

Substitute in the known values.

$\cos (θ) = \frac{- 2}{\sqrt{13}}$

Simplify the value of $\cos (θ)$ .

Move the negative in front of the fraction.

$\cos (θ) = - \frac{2}{\sqrt{13}}$

Multiply $\frac{2}{\sqrt{13}}$ by $\frac{\sqrt{13}}{\sqrt{13}}$ .

$\cos (θ) = - (\frac{2}{\sqrt{13}} \cdot \frac{\sqrt{13}}{\sqrt{13}})$

Combine and simplify the denominator.

Multiply $\frac{2}{\sqrt{13}}$ by $\frac{\sqrt{13}}{\sqrt{13}}$ .

$\cos (θ) = - \frac{2 \sqrt{13}}{\sqrt{13} \sqrt{13}}$

Raise $\sqrt{13}$ to the power of $1$ .

$\cos (θ) = - \frac{2 \sqrt{13}}{\sqrt{13} \sqrt{13}}$

Raise $\sqrt{13}$ to the power of $1$ .

$\cos (θ) = - \frac{2 \sqrt{13}}{\sqrt{13} \sqrt{13}}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\cos (θ) = - \frac{2 \sqrt{13}}{{\sqrt{13}}^{1 + 1}}$

Add $1$ and $1$ .

$\cos (θ) = - \frac{2 \sqrt{13}}{{\sqrt{13}}^{2}}$

Rewrite ${\sqrt{13}}^{2}$ as $13$ .

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{13}$ as $13^{\frac{1}{2}}$ .

$\cos (θ) = - \frac{2 \sqrt{13}}{{(13^{\frac{1}{2}})}^{2}}$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\cos (θ) = - \frac{2 \sqrt{13}}{13^{\frac{1}{2} \cdot 2}}$

Combine $\frac{1}{2}$ and $2$ .

$\cos (θ) = - \frac{2 \sqrt{13}}{13^{\frac{2}{2}}}$

Cancel the common factor of $2$ .

Cancel the common factor.

$\cos (θ) = - \frac{2 \sqrt{13}}{13^{\frac{2}{2}}}$

Rewrite the expression.

$\cos (θ) = - \frac{2 \sqrt{13}}{13}$

Evaluate the exponent.

$\cos (θ) = - \frac{2 \sqrt{13}}{13}$

Find the value of tangent.

Use the definition of tangent to find the value of $\tan (θ)$ .

$\tan (θ) = \frac{opp}{adj}$

Substitute in the known values.

$\tan (θ) = \frac{- 3}{- 2}$

Dividing two negative values results in a positive value.

$\tan (θ) = \frac{3}{2}$

Find the value of secant.

Use the definition of secant to find the value of $\sec (θ)$ .

$\sec (θ) = \frac{hyp}{adj}$

Substitute in the known values.

$\sec (θ) = \frac{\sqrt{13}}{- 2}$

Move the negative in front of the fraction.

$\sec (θ) = - \frac{\sqrt{13}}{2}$

Find the value of cosecant.

Use the definition of cosecant to find the value of $\csc (θ)$ .

$\csc (θ) = \frac{hyp}{opp}$

Substitute in the known values.

$\csc (θ) = \frac{\sqrt{13}}{- 3}$

Move the negative in front of the fraction.

$\csc (θ) = - \frac{\sqrt{13}}{3}$

This is the solution to each trig value.

$\sin (θ) = - \frac{3 \sqrt{13}}{13}$

$\cos (θ) = - \frac{2 \sqrt{13}}{13}$

$\tan (θ) = \frac{3}{2}$

$\cot (θ) = \frac{2}{3}$

$\sec (θ) = - \frac{\sqrt{13}}{2}$

$\csc (θ) = - \frac{\sqrt{13}}{3}$

Find the Other Trig Values in Quadrant III cot(theta)=2/3

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