Find the Oxidation Numbers As_2O_3

$A s_{2} O_{3}$

Step 1

Since $A s$ is in column $5$ of the periodic table, it will share $5$ electrons and use an oxidation state of $5$ .

$A s = 2 (5) = 10$

Step 2

Since $O$ is in column $6$ of the periodic table, it will share $6$ electrons and use an oxidation state of $6$ .

$O = 3 (- 2) = - 6$

Step 3

This is the full list of oxidation states for this molecule.

$A s = 10, O = - 6$