Find the Oxidation Numbers CrBr_3

$C r B r_{3}$

Step 1

Since $C r$ is in column $3$ of the periodic table, it will share $3$ electrons and use an oxidation state of $3$ .

$C r = 1 (3) = 3$

Step 2

Since $B r$ is in column $7$ of the periodic table, it will share $7$ electrons and use an oxidation state of $7$ .

$B r = 3 (- 1) = - 3$

Step 3

This is the full list of oxidation states for this molecule.

$C r = 3, B r = - 3$