Find the Oxidation Numbers Fe(C_2H_3O_2)

$F e (C_{2} H_{3} O_{2})$

Step 1

Since $F e$ is in column $3$ of the periodic table, it will share $3$ electrons and use an oxidation state of $3$ .

$F e = 1 (3) = 3$

Step 2

Since $O$ is in column $6$ of the periodic table, it will share $6$ electrons and use an oxidation state of $6$ .

$O = 2 (- 2) = - 4$

Step 3

Since $H$ is in column $1$ of the periodic table, it will share $1$ electrons and use an oxidation state of $1$ .

$H = 3 (1) = 3$

Step 4

Since $C$ is in column $4$ of the periodic table, it will share $4$ electrons and use an oxidation state of $4$ .

$C = 2 (- 4) = - 8$

Step 5

This is the full list of oxidation states for this molecule.

$F e = 3, O = - 4, H = 3, C = - 8$