Find the Oxidation Numbers H_2Te

$H_{2} T e$

Step 1

Since $T e$ is in column $6$ of the periodic table, it will share $6$ electrons and use an oxidation state of $6$ .

$T e = 1 (6) = 6$

Step 2

Since $H$ is in column $1$ of the periodic table, it will share $1$ electrons and use an oxidation state of $1$ .

$H = 2 (- 7) = - 14$

Step 3

This is the full list of oxidation states for this molecule.

$T e = 6, H = - 14$