Find the Oxidation Numbers HgO

$H g O$

Step 1

Since $H g$ is in column $0$ of the periodic table, it will share $0$ electrons and use an oxidation state of $0$ .

$H g = 1 (0) = 0$

Step 2

Since $O$ is in column $6$ of the periodic table, it will share $6$ electrons and use an oxidation state of $6$ .

$O = 1 (- 2) = - 2$

Step 3

This is the full list of oxidation states for this molecule.

$H g = 0, O = - 2$