Find the Oxidation Numbers MoS_2

$M o S_{2}$

Step 1

Since $M o$ is in column $3$ of the periodic table, it will share $3$ electrons and use an oxidation state of $3$ .

$M o = 1 (3) = 3$

Step 2

Since $S$ is in column $6$ of the periodic table, it will share $6$ electrons and use an oxidation state of $6$ .

$S = 2 (- 2) = - 4$

Step 3

This is the full list of oxidation states for this molecule.

$M o = 3, S = - 4$