Find the Oxidation Numbers Na_2Cr_6

$N a_{2} C r_{6}$

Step 1

Since $N a$ is in column $1$ of the periodic table, it will share $1$ electrons and use an oxidation state of $1$ .

$N a = 2 (1) = 2$

Step 2

Since $C r$ is in column $3$ of the periodic table, it will share $3$ electrons and use an oxidation state of $3$ .

$C r = 6 (- 5) = - 30$

Step 3

This is the full list of oxidation states for this molecule.

$N a = 2, C r = - 30$