Find the Oxidation Numbers NaCl+KBr

$N a C l + K B r$

Step 1

Since $K$ is in column $1$ of the periodic table, it will share $1$ electrons and use an oxidation state of $1$ .

$K = 1 (1) = 1$

Step 2

Since $C l$ is in column $7$ of the periodic table, it will share $7$ electrons and use an oxidation state of $7$ .

$C l = 1 (- 1) = - 1$

Step 3

Since $N a$ is in column $1$ of the periodic table, it will share $1$ electrons and use an oxidation state of $1$ .

$N a = 1 (1) = 1$

Step 4

Since $B r$ is in column $7$ of the periodic table, it will share $7$ electrons and use an oxidation state of $7$ .

$B r = 1 (- 1) = - 1$

Step 5

This is the full list of oxidation states for this molecule.

$K = 1, C l = - 1, N a = 1, B r = - 1$